12-Sided Die Odd Roll Count
Rolling a die for first odd number is an easy quant interview question on Expected Value, reported to have been seen at IMC.
MyQuantPartner is not affiliated with, endorsed by, or sponsored by these companies, and all trademarks belong to their respective owners.
This quant interview question is about randomness, repetition, and how long it takes for a simple event to occur when rolling a fair die. It uses a clean, discrete setup that is common in probability interviews and quant prep, where you repeatedly perform the same experiment and watch for a particular outcome. Top trading firms like such questions because they are quick to state yet require precise probabilistic thinking.
It trains understanding of distributions that model waiting times, as well as how to compute an average number of trials before a specified outcome is seen. It reinforces the link between event probability and expected time to see that event, and it sharpens intuition for independence and stationarity in repeated experiments.
This matters for quant interviews because real trading, risk, and market-making systems often hinge on timing of events: order arrivals, price jumps, or barrier hits. Interviewers use this kind of probability question to test whether a candidate can translate a simple probabilistic description into a clean expectation, reason about repeated trials under uncertainty, and connect the probability of an event with how long it will typically take to see it. Mastering these building-block questions is essential quant prep for more complex stochastic modeling, derivatives pricing, and algorithm design problems that appear in competitive quant interviews.
What it tests
Whenever you are asked for the expected number of independent trials until the first occurrence of a specific event, the problem is governed by the geometric distribution. This distribution arises because each trial is independent and has the same probability $p$ of success, so the process 'resets' after each failure. The key property is that the expected number of trials until the first success is always $1/p$, regardless of how many failures have occurred before. This is because the geometric distribution captures the 'memoryless' nature of such repeated, independent experiments: the probability structure is identical at every step. The principle holds because, after every failed attempt, the process is statistically identical to the original situation, so the expected remaining time is always the same as at the start, minus one for the trial just taken.
Practise this question with written feedback, or hear it in a spoken mock interview.
Get started free